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-y^2-5y+5=0
We add all the numbers together, and all the variables
-1y^2-5y+5=0
a = -1; b = -5; c = +5;
Δ = b2-4ac
Δ = -52-4·(-1)·5
Δ = 45
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{45}=\sqrt{9*5}=\sqrt{9}*\sqrt{5}=3\sqrt{5}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-3\sqrt{5}}{2*-1}=\frac{5-3\sqrt{5}}{-2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+3\sqrt{5}}{2*-1}=\frac{5+3\sqrt{5}}{-2} $
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